(20x^2)+1-[3((x^2)-7)+2]=0

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Solution for (20x^2)+1-[3((x^2)-7)+2]=0 equation:


Simplifying
(20x2) + 1 + -1[3((x2) + -7) + 2] = 0
(20x2) + 1 + -1[3(x2 + -7) + 2] = 0

Reorder the terms:
(20x2) + 1 + -1[3(-7 + x2) + 2] = 0
(20x2) + 1 + -1[(-7 * 3 + x2 * 3) + 2] = 0
(20x2) + 1 + -1[(-21 + 3x2) + 2] = 0

Reorder the terms:
(20x2) + 1 + -1[-21 + 2 + 3x2] = 0

Combine like terms: -21 + 2 = -19
(20x2) + 1 + -1[-19 + 3x2] = 0
(20x2) + 1 + [-19 * -1 + 3x2 * -1] = 0
(20x2) + 1 + [19 + -3x2] = 0

Reorder the terms:
1 + 19 + (20x2) + -3x2 = 0

Combine like terms: 1 + 19 = 20
20 + (20x2) + -3x2 = 0

Combine like terms: (20x2) + -3x2 = 17x2
20 + 17x2 = 0

Solving
20 + 17x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + 17x2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + 17x2 = 0 + -20
17x2 = 0 + -20

Combine like terms: 0 + -20 = -20
17x2 = -20

Divide each side by '17'.
x2 = -1.176470588

Simplifying
x2 = -1.176470588

Reorder the terms:
1.176470588 + x2 = -1.176470588 + 1.176470588

Combine like terms: -1.176470588 + 1.176470588 = 0.000000000
1.176470588 + x2 = 0.000000000

The solution to this equation could not be determined.

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